Convert exponential form to logarithmic form calculator

Names of standardized tests are owned by the trademark holders and are not affiliated with Varsity Tutors LLC.

4.9/5.0 Satisfaction Rating over the last 100,000 sessions. As of 4/27/18.

*See complete details for Better Score Guarantee.

Media outlet trademarks are owned by the respective media outlets and are not affiliated with Varsity Tutors.

Award-Winning claim based on CBS Local and Houston Press awards.

Varsity Tutors does not have affiliation with universities mentioned on its website.

Varsity Tutors connects learners with experts. Instructors are independent contractors who tailor their services to each client, using their own style, methods and materials.

1

Solved example of logarithmic equations

$log\left(x+1\right)=log\left(x-1\right)+3$

2

Express the numbers in the equation as logarithms of base $10$

$\log \left(x+1\right)=\log \left(x-1\right)+\log \left(10^{3}\right)$

$\log \left(x+1\right)-\log \left(x-1\right)=\log \left(1000\right)$

4

The difference of two logarithms of equal base $b$ is equal to the logarithm of the quotient: $\log_b(x)-\log_b(y)=\log_b\left(\frac{x}{y}\right)$

$\log \left(\frac{x+1}{x-1}\right)=\log \left(1000\right)$

5

For two logarithms of the same base to be equal, their arguments must be equal. In other words, if $\log(a)=\log(b)$ then $a$ must equal $b$

$\frac{x+1}{x-1}=1000$

6

Multiply both sides of the equation by $x-1$

$x+1=1000\left(x-1\right)$

7

Solve the product $1000\left(x-1\right)$

$x+1=1000x-1000$

8

We need to isolate the dependent variable $x$, we can do that by subtracting $1$ from both sides of the equation

$x=-1001+1000x$

10

Eliminate the $-999$ from the left side, multiplying both sides of the equation by the inverse of $-999$

$x=1.002002$

Verify that the solutions obtained are valid in the initial equation

11

The valid solutions to the logarithmic equation are the ones that, when replaced in the original equation, don't result in any logarithm of negative numbers or zero, since in those cases the logarithm does not exist

$x=1.002002$

Final Answer

$x=1.002002$

In convert Exponentials and Logarithms we will mainly discuss how to change the logarithm expression to Exponential expression and conversely from Exponential expression to logarithm expression.

To discus about convert Exponentials and Logarithms we need to first recall about logarithm and exponents.

The logarithm of any number to a given base is the index of the power to which the base must be raised in order to equal the given number. Thus, if aˣ = N, x is called the logarithm of N to the base a.

For example: 

1. Since 3⁴ = 81, the logarithm of 81 to base 3 is 4.

2. Since 10¹ = 10, 10² = 100, 10³ = 1000, ………….

The natural number 1, 2, 3, …… are respectively the logarithms of 10, 100, 1000, …… to base 10.

The logarithm of N to base a is usually written as log₀ N, so that the same meaning is expressed by the two equations

ax = N; x = loga N

Examples on convert Exponentials and Logarithms

1. Convert the following exponential form to logarithmic form:

(i) 104 = 10000

Solution:

104 = 10000

⇒ log10 10000 = 4

(ii) 3-5 = x

Solution:

3-5 = x

⇒ log3 x = -5

(iii) (0.3)3 = 0.027

Solution:

(0.3)3 = 0.027

⇒ log0.3 0.027 = 3

2. Convert the following logarithmic form to exponential form:

(i) log3 81 = 4

Solution:

log3 81 = 4

⇒ 34 = 81, which is the required exponential form.

(ii) log8 32 = 5/3

Solution:

log8 32 = 5/3

⇒ 85/3 = 32

(iii) log10 0.1 = -1

Solution:

log10 0.1 = -1

⇒ 10-1 = 0.1.

3. By converting to exponential form, find the values of following:

(i) log2 16

Solution:

Let log2 16 = x

⇒ 2x = 16

⇒ 2x = 24

⇒ x = 4,

Therefore, log2 16 = 4.

(ii) log3 (1/3)

Solution:

Let log3 (1/3) = x

⇒ 3x = 1/3

⇒ 3x = 3-1

⇒ x = -1,

Therefore, log3(1/3) = -1.

(iii) log5 0.008

Solution:

Let log5 0.008 = x

⇒ 5x = 0.008

⇒ 5x = 1/125

⇒ 5x = 5-3

⇒ x = -3,

Therefore, log5 0.008 = -3.

4. Solve the following for x:

(i) logx 243 = -5

Solution:

logx 243 = -5

⇒ x-5 = 243

⇒ x-5 = 35

⇒ x-5 = (1/3)-5

⇒ x = 1/3.

(ii) log√5 x = 4

Solution:

log√5 x = 4

⇒ x = (√5)4

⇒ x = (51/2)4

⇒ x = 52

⇒ x = 25.

(iii) log√x 8 = 6

Solution:

log√x 8 = 6

⇒ (√x)6 = 8

⇒ (x1/2)6 = 23

⇒ x3 = 23

⇒ x = 2.

Logarithmic Form Vs. Exponential Form

The logarithm function with base a has domain all positive real numbers and is defined by

loga M = x           ⇔           M = ax

                                                                 

where M > 0, a > 0, a ≠ 1

Logarithmic Form                          Exponential Form
loga M = x           ⇔           M = axLog7 49 = 2          ⇔           72 = 49

● Write the exponential equation in logarithmic form.


Exponential Form                          Logarithmic FormM = ax          ⇔           loga M = x

24 = 16          ⇔           log2 16 = 4

10-2 = 0.01          ⇔           log10 0.01 = -2

81/3 = 2          ⇔           log8 2 = 1/3

6-1 = 1/6          ⇔           log6 1/6 = -1

● Write the logarithmic equation in exponential form.


Logarithmic Form                          Exponential Formloga M = x           ⇔           M = axlog2 64 = 6          ⇔           26 = 64log4 32 = 5/2          ⇔          45/2= 32log1/82 = -1/3          ⇔           (1/8)-1/3 = 2log3 81 = x          ⇔           3x = 81log5 x = -2          ⇔           5-2 = xlog x = 3          ⇔          103 = x

● Solve for x:

1. log5 x = 2

x = 52

= 25

2. log81 x = ½

x = 811/2

⇒ x= (92)1/2

⇒ x = 9

3. log9 x = -1/2

x = 9-1/2

⇒ x = (32)-1/2

⇒ x = 3-1

⇒ x= 1/3

4. log7 x = 0

x= 70

⇒ x = 1

● Solve for n:

1. log3 27 = n

3n = 27

⇒ 3n = 33

⇒ n = 3

2. log10 10,000 = n

10n = 10,000

⇒ 10n = 104

⇒ n = 4

3. log49 1/7 = n

49n = 1/7

⇒ (72)n = 7-1

⇒ 72n = 7-1

⇒ 2n = -1

⇒ n = -1/2

4. log36 216 = n

36n = 216

⇒ (62)n = 63

⇒ 62n= 63

⇒ 2n = 3

⇒ n = 3/2

● Solve for b:

1. logb 27 = 3

b3 = 27

⇒ b3 = 33

⇒ b = 3

2. logb 4 = 1/2

b1/2 = 4

⇒ (b1/2)2 = 42

⇒ b = 16

3. logb 8 = -3

b-3 = 8 ⇒ b-3 = 23

⇒ (b-1)3 = 23

⇒b-1 = 2

⇒ 1/b = 2

⇒ b = ½

4. logb 49 = 2

b2 = 49

⇒ b2 = 72

⇒ b = 7

If f(x) = log3 x, find f(1).

Solution:

f(1) = log3 1 = 0 (since logarithm of 1 to any finite non-zero base is zero.)

Therefore f(1) = 0

A number that is domain of the function y = log10 x is

(a) 1

(b) 0

(c) ½

(d) =10

Answer: (b)

The graph of y = log4 x lines entirely in quadrants

(a) I and II

(b) II and III

(c) I and III

(d) I and IV

At what point does the graph of y = log5 x intersect the x-axis?

(a) (1, 0)

(b) (0, 1)

(c) (5, 0)

(d) There is no point of intersection.

Answer: (a)

 Mathematics Logarithm

Mathematics Logarithms

Convert Exponentials and Logarithms

Logarithm Rules or Log Rules

Solved Problems on Logarithm

Common Logarithm and Natural Logarithm

Antilogarithm

Didn't find what you were looking for? Or want to know more information about Math Only Math. Use this Google Search to find what you need.

How do you convert from exponential form to logarithmic form?

To convert from exponential to logarithmic form, we follow the same steps in reverse. We identify the base b, exponent x, and output y. Then we write x=logb(y) x = l o g b ( y ) .

What is the logarithmic form of the exponential?

The formula of log to exponential form is logaN=x l o g a N = x , is written in exponential form as ax=N a x = N . The logarithm of a number N to the base of a is equal to x, which if written in exponential form is equal to a to the exponent of x is equal to N.